Integrand size = 19, antiderivative size = 52 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^2} \, dx=-\frac {\cos (c+d x)}{a^2 d}+\frac {1}{d \left (a^2+a^2 \cos (c+d x)\right )}+\frac {2 \log (1+\cos (c+d x))}{a^2 d} \]
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Time = 0.12 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {3957, 2912, 12, 45} \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^2} \, dx=-\frac {\cos (c+d x)}{a^2 d}+\frac {1}{d \left (a^2 \cos (c+d x)+a^2\right )}+\frac {2 \log (\cos (c+d x)+1)}{a^2 d} \]
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Rule 12
Rule 45
Rule 2912
Rule 3957
Rubi steps \begin{align*} \text {integral}& = \int \frac {\cos ^2(c+d x) \sin (c+d x)}{(-a-a \cos (c+d x))^2} \, dx \\ & = \frac {\text {Subst}\left (\int \frac {x^2}{a^2 (-a+x)^2} \, dx,x,-a \cos (c+d x)\right )}{a d} \\ & = \frac {\text {Subst}\left (\int \frac {x^2}{(-a+x)^2} \, dx,x,-a \cos (c+d x)\right )}{a^3 d} \\ & = \frac {\text {Subst}\left (\int \left (1+\frac {a^2}{(a-x)^2}-\frac {2 a}{a-x}\right ) \, dx,x,-a \cos (c+d x)\right )}{a^3 d} \\ & = -\frac {\cos (c+d x)}{a^2 d}+\frac {1}{d \left (a^2+a^2 \cos (c+d x)\right )}+\frac {2 \log (1+\cos (c+d x))}{a^2 d} \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.23 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^2} \, dx=-\frac {\left (-3+\cos (2 (c+d x))-8 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )-8 \cos (c+d x) \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )\right ) \sec ^2\left (\frac {1}{2} (c+d x)\right )}{4 a^2 d} \]
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Time = 0.43 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.85
method | result | size |
parallelrisch | \(\frac {1-4 \ln \left (\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )-2 \cos \left (d x +c \right )+\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{2 a^{2} d}\) | \(44\) |
derivativedivides | \(\frac {-\frac {1}{1+\sec \left (d x +c \right )}+2 \ln \left (1+\sec \left (d x +c \right )\right )-\frac {1}{\sec \left (d x +c \right )}-2 \ln \left (\sec \left (d x +c \right )\right )}{d \,a^{2}}\) | \(51\) |
default | \(\frac {-\frac {1}{1+\sec \left (d x +c \right )}+2 \ln \left (1+\sec \left (d x +c \right )\right )-\frac {1}{\sec \left (d x +c \right )}-2 \ln \left (\sec \left (d x +c \right )\right )}{d \,a^{2}}\) | \(51\) |
norman | \(\frac {\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{2 d a}-\frac {5}{2 a d}}{a \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )}-\frac {2 \ln \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )}{a^{2} d}\) | \(71\) |
risch | \(-\frac {2 i x}{a^{2}}-\frac {{\mathrm e}^{i \left (d x +c \right )}}{2 a^{2} d}-\frac {{\mathrm e}^{-i \left (d x +c \right )}}{2 a^{2} d}-\frac {4 i c}{a^{2} d}+\frac {2 \,{\mathrm e}^{i \left (d x +c \right )}}{a^{2} d \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )^{2}}+\frac {4 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{a^{2} d}\) | \(103\) |
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Time = 0.28 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.12 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^2} \, dx=-\frac {\cos \left (d x + c\right )^{2} - 2 \, {\left (\cos \left (d x + c\right ) + 1\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) + \cos \left (d x + c\right ) - 1}{a^{2} d \cos \left (d x + c\right ) + a^{2} d} \]
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\[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^2} \, dx=\frac {\int \frac {\sin {\left (c + d x \right )}}{\sec ^{2}{\left (c + d x \right )} + 2 \sec {\left (c + d x \right )} + 1}\, dx}{a^{2}} \]
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Time = 0.21 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.88 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^2} \, dx=\frac {\frac {1}{a^{2} \cos \left (d x + c\right ) + a^{2}} - \frac {\cos \left (d x + c\right )}{a^{2}} + \frac {2 \, \log \left (\cos \left (d x + c\right ) + 1\right )}{a^{2}}}{d} \]
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Time = 0.34 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.00 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^2} \, dx=-\frac {\cos \left (d x + c\right )}{a^{2} d} + \frac {2 \, \log \left ({\left | -\cos \left (d x + c\right ) - 1 \right |}\right )}{a^{2} d} + \frac {1}{a^{2} d {\left (\cos \left (d x + c\right ) + 1\right )}} \]
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Time = 0.09 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.88 \[ \int \frac {\sin (c+d x)}{(a+a \sec (c+d x))^2} \, dx=\frac {2\,\ln \left (\cos \left (c+d\,x\right )+1\right )}{a^2\,d}-\frac {{\cos \left (c+d\,x\right )}^2-2}{a^2\,d\,\left (\cos \left (c+d\,x\right )+1\right )} \]
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